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प्रश्न
What will be the value of sin 45° + `1/sqrt(2)`?
विकल्प
`1 + sqrt(2)`
`2sqrt(2)`
`1/sqrt(2)`
`sqrt(2)`
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उत्तर
`sqrt(2)`
Explanation:
sin 45° + `1/sqrt(2) = 1/sqrt(2) + 1/sqrt(2)` .....`[∵ sin^circ = 1/sqrt(2)]`
= `(1 + 1)/sqrt(2)`
= `2/sqrt(2)`
= `2/sqrt(2) xx sqrt(2)/sqrt(2)`
= `(2sqrt(2))/2`
= `sqrt(2)`
Thus, the value of sin 45° + `1/sqrt(2)` is `sqrt(2)`.
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∴ L.H.S. = R.H.S.
∴ cot θ + tan θ = cosec·sec θ
