हिंदी

Find will be the value of cos 90° + sin 90°.

Advertisements
Advertisements

प्रश्न

Find will be the value of cos 90° + sin 90°.

योग
Advertisements

उत्तर

cos 90° = 0 and sin 90° = 1

∴ cos 90° + sin 90° = 0 + 1 = 1

Hence, the value of cos 90° + sin 90° is 1.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2025-2026 (March) Model set 2 by shaalaa.com

संबंधित प्रश्न

If sin A = `3/4`, calculate cos A and tan A.


If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.


If 4 tan θ = 3, evaluate `((4sin theta - cos theta + 1)/(4sin theta + cos theta - 1))`


In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`cosec theta = sqrt10`


In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`cos theta = 12/2`


If `cot theta = 1/sqrt3` show that  `(1 - cos^2 theta)/(2 - sin^2  theta) = 3/5`


If `tan theta = 1/sqrt7`     `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + sec^2 theta) = 3/4`


if `sec A = 17/8` verify that `(3 - 4sin^2A)/(4 cos^2 A - 3) = (3 - tan^2 A)/(1 - 3 tan^2 A)`


Evaluate the following

sin2 30° + sin2 45° + sin2 60° + sin2 90°


Evaluate the following

cos2 30° + cos2 45° + cos2 60° + cos2 90°


Evaluate the Following

4(sin4 30° + cos2 60°) − 3(cos2 45° − sin2 90°) − sin2 60°


Find the value of x in the following :

`2 sin  x/2 = 1`


If sin (A − B) = sin A cos B − cos A sin B and cos (A − B) = cos A cos B + sin A sin B, find the values of sin 15° and cos 15°.


If cos (40° + A) = sin 30°, then value of A is ______.


If cos A + cos² A = 1, then sin² A + sin4 A is equal to ______.


If cos (81 + θ)° = sin`("k"/3 - theta)^circ` where θ is an acute angle, then the value of k is ______.


5 tan² A – 5 sec² A + 1 is equal to ______.


If sinθ = `1/sqrt(2)` and `π/2 < θ < π`. Then the value of `(sinθ + cosθ)/tanθ` is ______.


In ΔBC, right angled at C, if tan A = `8/7`, then the value of cot B is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×