Advertisements
Advertisements
प्रश्न
Find will be the value of cos 90° + sin 90°.
Advertisements
उत्तर
cos 90° = 0 and sin 90° = 1
∴ cos 90° + sin 90° = 0 + 1 = 1
Hence, the value of cos 90° + sin 90° is 1.
APPEARS IN
संबंधित प्रश्न
In Given Figure, find tan P – cot R.

If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
Prove that `(sin "A" - 2sin^3 "A")/(2cos^3 "A" - cos "A") = tan "A"`
In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.
`cosec theta = sqrt10`
If `sec θ = 13/5`, show that `(2 sin θ - 3 cos θ)/(4 sin θ - 9 cos θ) = 3`.
If `cot theta = 1/sqrt3` show that `(1 - cos^2 theta)/(2 - sin^2 theta) = 3/5`
If `tan θ = 20/21` show that `(1 - sin theta + cos theta)/(1 + sin theta + cos theta) = 3/7`
Evaluate the Following
cosec3 30° cos 60° tan3 45° sin2 90° sec2 45° cot 30°
Evaluate the Following
`cot^2 30^@ - 2 cos^2 60^circ- 3/4 sec^2 45^@ - 4 sec^2 30^@`
Evaluate the Following:
`(tan^2 60^@ + 4 cos^2 45^@ + 3 sec^2 30^@ + 5 cos^2 90)/(cosec 30^@ + sec 60^@ - cot^2 30^@)`
sin (45° + θ) – cos (45° – θ) is equal to ______.
Find the value of sin 0° + cos 0° + tan 0° + sec 0°.
Prove that: cot θ + tan θ = cosec θ·sec θ
Proof: L.H.S. = cot θ + tan θ
= `square/square + square/square` ......`[∵ cot θ = square/square, tan θ = square/square]`
= `(square + square)/(square xx square)` .....`[∵ square + square = 1]`
= `1/(square xx square)`
= `1/square xx 1/square`
= cosec θ·sec θ ......`[∵ "cosec" θ = 1/square, sec θ = 1/square]`
= R.H.S.
∴ L.H.S. = R.H.S.
∴ cot θ + tan θ = cosec·sec θ
If f(x) = `3cos(x + (5π)/6) - 5sinx + 2`, then maximum value of f(x) is ______.
If θ is an acute angle of a right angled triangle, then which of the following equation is not true?
If sin θ – cos θ = 0, then find the value of sin4 θ + cos4 θ.
In ΔBC, right angled at C, if tan A = `8/7`, then the value of cot B is ______.

