рд╣рд┐рдВрджреА

In the Following, One of the Six Trigonometric Ratios is Given. Find the Values of the Other Trigonometric Ratios. `Cos Theta = 12/2` - Mathematics

Advertisements
Advertisements

рдкреНрд░рд╢реНрди

In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`cos theta = 12/2`

Advertisements

рдЙрддреНрддрд░

`cos theta = "ЁЭСОЁЭССЁЭСЧЁЭСОЁЭСРЁЭСТЁЭСЫЁЭСб ЁЭСаЁЭСЦЁЭССЁЭСТ"/"тДОЁЭСжЁЭСЭЁЭСЬЁЭСбЁЭСТЁЭСЫЁЭСвЁЭСаЁЭСТ" = 12/15`

Let x be the opposite side.

By applying Pythagoras theorem

ЁЭР┤ЁЭР╢2 = ЁЭР┤ЁЭР╡2 + ЁЭР╡ЁЭР╢2

225 = ЁЭСе2 + 144

225 − 144 = ЁЭСе2

ЁЭСе2 = 81

ЁЭСе = 9

`sin theta = "ЁЭСЬЁЭСЭЁЭСЭЁЭСЬЁЭСаЁЭСЦЁЭСбЁЭСТ ЁЭСаЁЭСЦЁЭССЁЭСТ"/"тДОЁЭСжЁЭСЭЁЭСЬЁЭСбЁЭСТЁЭСЫЁЭСвЁЭСаЁЭСТ" = 9/15`

`tan theta = "ЁЭСЬЁЭСЭЁЭСЭЁЭСЬЁЭСаЁЭСЦЁЭСбЁЭСТ ЁЭСаЁЭСЦЁЭССЁЭСТ"/"ЁЭСОЁЭССЁЭСЧЁЭСОЁЭСРЁЭСТЁЭСЫЁЭСб ЁЭСаЁЭСЦЁЭССЁЭСТ" = 9/12`

`cosec theta = 1/sin theta = (1/9)/15 = 15/9`

`sec theta = 1/cos theta = (1/12)/15 = 15/12`

`cot theta = 1/tan theta = (1/9)/12 = 12/9`

shaalaa.com
  рдХреНрдпрд╛ рдЗрд╕ рдкреНрд░рд╢реНрди рдпрд╛ рдЙрддреНрддрд░ рдореЗрдВ рдХреЛрдИ рддреНрд░реБрдЯрд┐ рд╣реИ?
рдЕрдзреНрдпрд╛рдп 10: Trigonometric Ratios - Exercise 10.1 [рдкреГрд╖реНрда реирей]

APPEARS IN

рдЖрд░рдбреА рд╢рд░реНрдорд╛ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 10 Trigonometric Ratios
Exercise 10.1 | Q 1.12 | рдкреГрд╖реНрда реирей

рд╡реАрдбрд┐рдпреЛ рдЯреНрдпреВрдЯреЛрд░рд┐рдпрд▓VIEW ALL [2]

рд╕рдВрдмрдВрдзрд┐рдд рдкреНрд░рд╢реНрди

 In Given Figure, find tan P – cot R.


Given sec θ = `13/12`, calculate all other trigonometric ratios.


In ΔABC, right angled at B. If tan A = `1/sqrt3` , find the value of

  1.  sin A cos C + cos A sin C
  2. cos A cos C − sin A sin C

In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`sin theta = 11/5`


In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`cos theta = 7/25`


In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`sec theta = 13/5`


If `tan theta = a/b`, find the value of `(cos theta + sin theta)/(cos theta - sin theta)`


If sin θ = `12/13`, Find `(sin^2 θ - cos^2 θ)/(2sin θ cos θ) × 1/(tan^2 θ)`.


if `cot theta = 3/4` prove that `sqrt((sec theta - cosec theta)/(sec theta +cosec theta)) = 1/sqrt7`


Evaluate the following

cos2 30° + cos2 45° + cos2 60° + cos2 90°


Find the value of x in the following :

`2 sin  x/2 = 1`


Find the value of x in each of the following :

cos x = cos 60º cos 30º + sin 60º sin 30º


sin (45° + θ) – cos (45° – θ) is equal to ______.


If cos A = `4/5`, then the value of tan A is ______.


Given that sinα = `1/2` and cosβ = `1/2`, then the value of (α + β) is ______.


The value of the expression `[(sin^2 22^circ + sin^2 68^circ)/(cos^2 22^circ + cos^2 68^circ) + sin^2 63^circ + cos 63^circ sin 27^circ]` is ______.


Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.

Proof: L.H.S. = sec θ + tan θ

= `1/square + square/square`

= `square/square`  ......`(тИ╡ sec θ = 1/square, tan θ = square/square)`

= `((1 + sin θ) square)/(cos θ  square)`  ......[Multiplying `square` with the numerator and denominator]

= `(1^2 - square)/(cos θ  square)`

= `square/(cos θ  square)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`


If sec θ = `1/2`, what will be the value of cos θ?


`sqrt(3)` cos2A + `sqrt(3)` sin2A is equal to ______.


Evaluate: 5 cosec2 45° – 3 sin2 90° + 5 cos 0°.


Share
Notifications

Englishрд╣рд┐рдВрджреАрдорд░рд╛рдареА


      Forgot password?
Use app×