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If 3 cot θ = 2, find the value of 4sinθ-3cosθ2sinθ+6cosθ. - Mathematics

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प्रश्न

If 3 cot θ = 2, find the value of  `(4sin theta - 3 cos theta)/(2 sin theta + 6cos theta)`.

योग
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उत्तर

`cot theta = 2/3`

`= ((4 sin theta - 3 cos theta)/sin theta)/((2sin theta + 6 cos theta)/sin theta)`

`= (4 - 3 cot theta)/(2 + 6 cot theta)`

`= (4 - 3 xx 2/3)/(2 + 6 xx 2/3)`

`= (4 + 2)/(2 + 4) = 2/6`

`= 1/3`

 

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अध्याय 10: Trigonometric Ratios - Exercise 10.1 [पृष्ठ २४]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 10 Trigonometric Ratios
Exercise 10.1 | Q 11 | पृष्ठ २४

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