Advertisements
Advertisements
प्रश्न
Find an acute angle θ when `(cos θ - sin θ)/(cos θ + sin θ) = (1 - sqrt(3))/(1 + sqrt(3))`
Advertisements
उत्तर
Given, `(cos θ - sin θ)/(cos θ + sin θ) = (1 - sqrt(3))/(1 + sqrt(3))`
Cross multiplying
`(1 + sqrt(3)) (cos θ - sin θ) = (1 - sqrt(3)) (cos θ + sin θ)`
`1(cos θ - sin θ) + sqrt(3)(cos θ - sin θ) = 1(cosθ + sin θ) - sqrt(3) (cos θ + sin θ)`
`cos θ - sin θ + sqrt(3)cos θ - sqrt(3)sin θ = cos θ + sin θ - sqrt(3) cos θ - sqrt(3)sin θ - sin θ + sqrt(3)cos θ = sin θ - sqrt(3)cos θ`
`sqrt(3)cos θ + sqrt(3) cos θ` = sin θ + sin θ
`2sqrt(3)cos θ` = 2 sin θ
`sqrt(3)cos θ` = sin θ
`sqrt(3) = sinθ/cosθ`
tan θ = `sqrt(3)`
Since tan 60° = `sqrt(3)`
Therefore, θ = 60°
APPEARS IN
संबंधित प्रश्न
In ΔPQR, right angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
if `sin theta = 3/4` prove that `sqrt(cosec^2 theta - cot)/(sec^2 theta - 1) = sqrt7/3`
Evaluate the following
`2 sin^2 30^2 - 3 cos^2 45^2 + tan^2 60^@`
Evaluate the Following
(cos 0° + sin 45° + sin 30°)(sin 90° − cos 45° + cos 60°)
Evaluate the Following:
`(tan^2 60^@ + 4 cos^2 45^@ + 3 sec^2 30^@ + 5 cos^2 90)/(cosec 30^@ + sec 60^@ - cot^2 30^@)`
Find the value of x in the following :
`sqrt3 tan 2x = cos 60^@ + sin45^@ cos 45^@`
If `sqrt2 sin (60° – α) = 1` then α is ______.
5 tan² A – 5 sec² A + 1 is equal to ______.
If sin A = `1/2`, then the value of cot A is ______.
In ΔBC, right angled at C, if tan A = `8/7`, then the value of cot B is ______.

