मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

What will be the value of sin 45° + 12?

Advertisements
Advertisements

प्रश्न

What will be the value of sin 45° + `1/sqrt(2)`?

पर्याय

  • `1 + sqrt(2)`

  • `2sqrt(2)`

  • `1/sqrt(2)`

  • `sqrt(2)`

MCQ
Advertisements

उत्तर

`sqrt(2)`

Explanation:

sin 45° + `1/sqrt(2) = 1/sqrt(2) + 1/sqrt(2)`  .....`[∵ sin^circ = 1/sqrt(2)]`

= `(1 + 1)/sqrt(2)`

= `2/sqrt(2)`

= `2/sqrt(2) xx sqrt(2)/sqrt(2)`

= `(2sqrt(2))/2`

= `sqrt(2)`

Thus, the value of sin 45° + `1/sqrt(2)` is `sqrt(2)`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2025-2026 (March) Model set 3 by shaalaa.com

संबंधित प्रश्‍न

If 4 tan θ = 3, evaluate `((4sin theta - cos theta + 1)/(4sin theta + cos theta - 1))`


In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`sec theta = 13/5`


In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`cos theta = 12/2`


If sin θ = `12/13`, Find `(sin^2 θ - cos^2 θ)/(2sin θ cos θ) × 1/(tan^2 θ)`.


if `cos theta = 3/5`, find the value of `(sin theta - 1/(tan theta))/(2 tan theta)`


if `sec A = 17/8` verify that `(3 - 4sin^2A)/(4 cos^2 A - 3) = (3 - tan^2 A)/(1 - 3 tan^2 A)`


If `tan theta = 24/7`, find that sin θ + cos θ.


If `sin theta = a/b` find sec θ + tan θ in terms of a and b.


If `tan θ = 20/21` show that `(1 - sin theta + cos theta)/(1 + sin theta + cos theta) = 3/7`


Evaluate the Following

cosec3 30° cos 60° tan3 45° sin2 90° sec2 45° cot 30°


Evaluate the following:

(cos 0° + sin 45° + sin 30°)(sin 90° – cos 45° + cos 60°)


Evaluate the Following:

`(tan^2 60^@ + 4 cos^2 45^@ + 3 sec^2 30^@ + 5 cos^2 90)/(cosec 30^@ + sec 60^@ - cot^2 30^@)`


Find the value of x in the following :

`2 sin  x/2 = 1`


Find the value of x in the following :

`sqrt3 tan 2x = cos 60^@ + sin45^@ cos 45^@`


If sin (A − B) = sin A cos B − cos A sin B and cos (A − B) = cos A cos B + sin A sin B, find the values of sin 15° and cos 15°.


In ΔABC is a right triangle such that ∠C = 90° ∠A = 45°, BC = 7 units find ∠B, AB and AC


In the given figure, if sin θ = `7/13`, which angle will be θ?


Prove that: cot θ + tan θ = cosec θ·sec θ

Proof: L.H.S. = cot θ + tan θ

= `square/square + square/square`  ......`[∵ cot θ = square/square, tan θ = square/square]`

= `(square + square)/(square xx square)`  .....`[∵ square + square = 1]`

= `1/(square xx square)`

= `1/square xx 1/square`

= cosec θ·sec θ  ......`[∵ "cosec"  θ = 1/square, sec θ = 1/square]`

= R.H.S.

∴ L.H.S. = R.H.S.

∴ cot θ + tan θ = cosec·sec θ


If `θ∈[(5π)/2, 3π]` and 2cosθ + sinθ = 1, then the value of 7cosθ + 6sinθ is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×