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प्रश्न
In a right triangle PQR, right angled at Q. If tan P = `sqrt(3)`, then evaluate 2 sin P cos P.
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उत्तर
We have,
`\implies` tan P = `sqrt(3)`
`\implies` tan P = `(RQ)/(PQ)`
= `sqrt(3)`
= tan 60°
`\implies` P = 60°
So, 2 sin P cos P = 2 × 60° × cos 60°
= `2 xx sqrt(3)/2 xx 1/2`
= `sqrt(3)/2`
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