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प्रश्न
In the adjoining figure, PT is a tangent at T to the circle with centre O. If ∠TPO = 30°, find the value of x.
बेरीज
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उत्तर
Given:
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PT is a tangent to the circle at point T.
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O is the centre of the circle.
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∠TPO = 30°.
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We have to find ∠x = ∠PTO.
The radius OT is perpendicular to the tangent PT at the point of contact T.
∴ ∠OTP = 90°
∠OTP = 90°, ∠TPO = 30°, ∠x = ?
The sum of angles in a triangle = 180°
∠OTP + ∠TPO + ∠x = 180°
90° + 30° + x = 180°
x = 180° − 120° = 60°
x = 60°
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