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If cosθ=35, find the value of sinθ-1tanθ2tanθ - Mathematics

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प्रश्न

if `cos theta = 3/5`, find the value of `(sin theta - 1/(tan theta))/(2 tan theta)`

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उत्तर

We know that `cos theta = "𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑠𝑖𝑑𝑒"/"ℎ𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒"`

Let us consider right angled Δle ABC

Let x be the opposite side, By applying Pythagoras theorem

𝐴𝐶2 = 𝐴𝐵2 + 𝐵𝐶2

25 = 𝑥2 + 9

𝑥2 = 16 ⇒ 𝑥 = 4

`sin theta = (AB)/(AC) = 4/5`

`tan theta = (AB)/(BC) = 4/3`

Substitute sin 𝜃, tan 𝜃 in the equation we get

`(sin theta 1/(tan theta))/(2 tan theta) = (4/5 - 3/4)/(2 xx 4/3)`

`= ((16 - 15)/20)/(8/3)`

= `(1/20)/(8/3)`

`=  1/20 xx  8/3 = 3/160`

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पाठ 10: Trigonometric Ratios - Exercise 10.1 [पृष्ठ २५]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 10 Trigonometric Ratios
Exercise 10.1 | Q 21 | पृष्ठ २५

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