मराठी

Evaluate the Following Sin2 30° + Sin2 45° + Sin2 60° + Sin2 90°

Advertisements
Advertisements

प्रश्न

Evaluate the following

sin2 30° + sin2 45° + sin2 60° + sin2 90°

Advertisements

उत्तर

sin2 30° + sin2 45° + sin2 60° + sin2 90°  .....(1)

`sin 30^@ = 1/2     sin 45^@ = 1/sqrt2`

`sin 60^@ = sqrt3/2   sin 90^@ = 1`

By substituting above values in (i), we get

`= [1/2]^2 + [1/sqrt2]^2 + [sqrt3/2]^2 + [1]^2`

`= 1/4 + 1/2 + 3/4 + 1 => (1 + 3)/4 + (1 + 2)/2`

`=> 1 + 3/2 = (2 + 3)/2 = 5/2`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Trigonometric Ratios - Exercise 10.2 [पृष्ठ ४१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 10
पाठ 10 Trigonometric Ratios
Exercise 10.2 | Q 4 | पृष्ठ ४१

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine:

sin A, cos A


In ΔPQR, right angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.


State whether the following are true or false. Justify your answer.

sec A = `12/5` for some value of angle A.


State whether the following are true or false. Justify your answer.

cot A is the product of cot and A.


If tan θ = `a/b` prove that `(a sin theta - b cos theta)/(a sin theta + b cos theta) = (a^2 - b^2)/(a^2 + b^2)`


if `cos theta = 3/5`, find the value of `(sin theta - 1/(tan theta))/(2 tan theta)`


If `tan theta = 24/7`, find that sin θ + cos θ.


Evaluate the Following

4(sin4 60° + cos4 30°) − 3(tan2 60° − tan2 45°) + 5 cos2 45°


Evaluate the Following

cosec3 30° cos 60° tan3 45° sin2 90° sec2 45° cot 30°


Evaluate the Following

`cot^2 30^@ - 2 cos^2 60^circ- 3/4 sec^2 45^@ - 4 sec^2 30^@`


Evaluate the Following

`(sin 30^@ - sin 90^2 + 2 cos 0^@)/(tan 30^@ tan 60^@)`


Evaluate the Following

`sin 30^2/sin 45^@ + tan 45^@/sec 60^@ - sin 60^@/cot 45^@ - cos 30^@/sin 90^@`


Evaluate the Following:

`tan 45^@/(cosec 30^@) + sec 60^@/cot 45^@  - (5 sin 90^@)/(2 cos 0^@)`


If `sqrt2 sin (60° – α) = 1` then α is ______.


If cos A = `4/5`, then the value of tan A is ______.


In ΔABC, ∠ABC = 90° and ∠ACB = θ. Then write the ratios of sin θ and tan θ from the figure.


Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.

Proof: L.H.S. = sec θ + tan θ

= `1/square + square/square`

= `square/square`  ......`(∵ sec θ = 1/square, tan θ = square/square)`

= `((1 + sin θ) square)/(cos θ  square)`  ......[Multiplying `square` with the numerator and denominator]

= `(1^2 - square)/(cos θ  square)`

= `square/(cos θ  square)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`


Find an acute angle θ when `(cos θ - sin θ)/(cos θ + sin θ) = (1 - sqrt(3))/(1 + sqrt(3))`


The maximum value of the expression 5cosα + 12sinα – 8 is equal to ______.


If sin θ – cos θ = 0, then find the value of sin4 θ + cos4 θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×