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प्रश्न
Evaluate: 5 cosec2 45° – 3 sin2 90° + 5 cos 0°.
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उत्तर
5 cosec2 45° – 3 sin2 90° + 5 cos 0°
= `5(sqrt(2))^2 - 3(1)^2 + 5(1)`
= 10 – 3 + 5
= 12.
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