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प्रश्न
If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = ______.
विकल्प
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उत्तर
If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = 2.
Explanation:
Now, tan θ + cot θ = `sinθ/cosθ + cosθ/sinθ`
= `(sin^2θ + cos^2θ)/(cosθ sinθ)`
Putting sin2θ + cos2θ = 1
= `1/(cosθ sinθ)` .....(1)
Finding cos θ sin θ
sin θ + cos θ = `sqrt(2)`
Squaring both sides
(sin θ + cos θ)2 = `(sqrt(3))^2`
(sin θ + cos θ)2 = 2
sin2θ + cos2θ + 2 sin θ cos θ = 2
Putting sin2θ + cos2θ = 1
1 + 2 sin θ cos θ = 2
2 sin θ cos θ = 2 – 1
2 sin θ cos θ = 1
sin θ cos θ = `1/2`
cos θ sin θ = `1/2`
Now, tan θ + cot θ = `1/(cos θ sin θ)`
Putting values
= `1/(1/2)`
= 2
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Prove that: cot θ + tan θ = cosec θ·sec θ
Proof: L.H.S. = cot θ + tan θ
= `square/square + square/square` ......`[∵ cot θ = square/square, tan θ = square/square]`
= `(square + square)/(square xx square)` .....`[∵ square + square = 1]`
= `1/(square xx square)`
= `1/square xx 1/square`
= cosec θ·sec θ ......`[∵ "cosec" θ = 1/square, sec θ = 1/square]`
= R.H.S.
∴ L.H.S. = R.H.S.
∴ cot θ + tan θ = cosec·sec θ
