Advertisements
Advertisements
प्रश्न
If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = ______.
पर्याय
1
2
3
4
Advertisements
उत्तर
If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = 2.
Explanation:
Now, tan θ + cot θ = `sinθ/cosθ + cosθ/sinθ`
= `(sin^2θ + cos^2θ)/(cosθ sinθ)`
Putting sin2θ + cos2θ = 1
= `1/(cosθ sinθ)` .....(1)
Finding cos θ sin θ
sin θ + cos θ = `sqrt(2)`
Squaring both sides
(sin θ + cos θ)2 = `(sqrt(3))^2`
(sin θ + cos θ)2 = 2
sin2θ + cos2θ + 2 sin θ cos θ = 2
Putting sin2θ + cos2θ = 1
1 + 2 sin θ cos θ = 2
2 sin θ cos θ = 2 – 1
2 sin θ cos θ = 1
sin θ cos θ = `1/2`
cos θ sin θ = `1/2`
Now, tan θ + cot θ = `1/(cos θ sin θ)`
Putting values
= `1/(1/2)`
= 2
APPEARS IN
संबंधित प्रश्न
If sin A = `3/4`, calculate cos A and tan A.
Evaluate the following
cos 60° cos 45° - sin 60° ∙ sin 45°
Evaluate the following
`2 sin^2 30^2 - 3 cos^2 45^2 + tan^2 60^@`
Evaluate the Following
`cot^2 30^@ - 2 cos^2 60^circ- 3/4 sec^2 45^@ - 4 sec^2 30^@`
`(1 + tan^2 "A")/(1 + cot^2 "A")` is equal to ______.
The value of cos 0°. cos 1°. cos 2°. cos 3°… cos 89° cos 90° is ______.
5 tan² A – 5 sec² A + 1 is equal to ______.
Given that sinα = `1/2` and cosβ = `1/2`, then the value of (α + β) is ______.
Prove that `tan θ/(1 - cot θ) + cot θ/(1 - tanθ)` = 1 + sec θ cosec θ
If sinθ = `1/sqrt(2)` and `π/2 < θ < π`. Then the value of `(sinθ + cosθ)/tanθ` is ______.
