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Question
If `tan theta = 24/7`, find that sin θ + cos θ.
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Solution
Let x be the hypotenuse.
In Δ ABC, by applying Pythagoras theorem.
AC2 = AB2 + BC2
x2 = (24)2 + (7)2
x2 = 576 + 49
x2 = 625
x = `sqrt(625)`
x = 25
`sin theta = (AB)/(AC) = 24/25`
`cos theta = (BC)/(AC) = 7/25`
∴ `sin theta + cos theta = 24/25 + 7/25`
`= 31/25`
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