Question

In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine:

sin A, cos A

Answer 1

ΔABC is right angled at B

AB = 24 cm, BC = 7 cm

Let ‘x’ be the hypotenuse,

By applying Pythagoras

AC² = AB² + BC²

x² = 242 + 72

x² = 576 + 49

x² = 625

x = 25

For Sin A, Cos A

At ∠A, opposite side = 7

adjacent side = 24

hypotenuse = 25

sin A = `"opposite side"/"hypotenuse" =("BC")/("AC") =  7/25`

cos A = `"adjacent side"/"hypotenuse" = ("AB")/("AC") = 24/25`