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Question
If ΔXYZ ~ ΔPQR then `"XY"/"PQ" = "YZ"/"QR"` = ?
Options
`"XZ"/"PR"`
`"XZ"/"PQ"`
`"XZ"/"QR"`
`"YZ"/"PQ"`
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Solution
`"XZ"/"PR"`
In ΔXYZ and ΔPQR,
ΔXYZ ~ ΔPQR ...(Given)
`"XY"/"PQ" = "YZ"/"QR" = "XZ"/"PR"` ...[Corresponding sides of similar triangles.]
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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.

Given: PQ ⊥ BC, AD ⊥ BC
Now, A(ΔPQB) = `1/2 xx square xx square`
A(ΔPBC) = `1/2 xx square xx square`
Therefore,
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= `square/square`
