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Question
If the sum of the zeros of the quadratic polynomial f(t) = kt2 + 2t + 3k is equal to their product, find the value of k.
Sum
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Solution
Let the two zeroes of the f(t) = kt2 + 2t + 3k be α and β
Sum of the zeroes (α + β)
Product of the zeroes αβ
`(-2)/k=(3k)/k`
`-2k = 3k^2`
`2k + 3k^2 = 0`
`k(3k + 2) = 0`
`k = 0`
`k=(-2)/3`
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