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If P is a Real Number and If the Middle Term in the Expansion of ( P 2 + 2 ) 8 is 1120, Find P.

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Question

If p is a real number and if the middle term in the expansion of  \[\left( \frac{p}{2} + 2 \right)^8\] is 1120, find p.

 
 
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Solution

In the binomial expansion of \[\left( \frac{p}{2} + 2 \right)^8\] , we observe that  \[\left( \frac{8}{2} + 1 \right)^{th}\]  i.e., 5th term is the middle term.

It is given that the middle term is 1120.

\[\therefore T_5 = 1120\]

\[ \Rightarrow^8 C_4 \left( \frac{p}{2} \right)^{8 - 4} \left( 2 \right)^4 = 1120\]

\[ \Rightarrow p^4 = 16\]

\[ \Rightarrow p = \pm 2\] 

Hence, the real values of p is \[\pm 2\]

 
 
  
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Chapter 18: Binomial Theorem - Exercise 18.2 [Page 40]

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R.D. Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.2 | Q 37 | Page 40

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