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The Middle Term in the Expansion of ( 2 X 3 − 3 2 X 2 ) 2 N is (A) 2 N C N(B) ( − 1 ) N 2 N C N X − N(C) 2 N C N X − N(D) None of These

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Question

The middle term in the expansion of \[\left( \frac{2x}{3} - \frac{3}{2 x^2} \right)^{2n}\] is 

 

Options

  • \[^{2n}{}{C}_n\]

     

  • `\left( - 1 \right)^n "^2 n C_n x^{- n}`

     

  •  \[^{2n}{}{C}_n x^{- n}\]

     

  •  none of these

     
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Solution

`\left( - 1 \right)^n "^2 n C_n x^{- n}`

\[\text{ Here, n is even} \]
\[\text{ Middle term in the given expansion }  = \left( \frac{2n}{2} + 1 \right)\text{ th = (n + 1)th term } \]
\[ = ^{2n}{}{C}_n \left( \frac{2x}{3} \right)^{2n - n} \left( \frac{- 3}{2 x^2} \right)^n \]
`= ( - 1 )^n "^2nC_n x^{- n}`

 

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Chapter 18: Binomial Theorem - Exercise 18.4 [Page 48]

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R.D. Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.4 | Q 29 | Page 48

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