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Maharashtra State BoardSSC (English Medium) 10th Standard

From given figure, In ∆ABC, If AC = 12 cm. then AB = ? Activity: From given figure, In ∆ABC, ∠ABC = 90°, ∠ACB = 30° ∴ ∠BAC = □ ∴ ∆ABC is 30° – 60° – 90° triangle.

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Question

From given figure, In ∆ABC, If AC = 12 cm. then AB = ?


Activity: From given figure, In ∆ABC, ∠ABC = 90°, ∠ACB = 30°

∠BAC = `square`

∴ ∆ABC is 30° – 60° – 90° triangle.

∴ In ∆ABC by property of 30° – 60° – 90° triangle.

∴ AB = `1/2` AC and `square` = `sqrt(3)/2` AC

∴ `square` = `1/2 xx 12` and BC = `sqrt(3)/2 xx 12`

∴ `square` = 6 and BC = `6sqrt(3)`

Activity
Sum
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Solution

From given figure, In ∆ABC, ∠ABC = 90°, ∠ACB = 30°

∠BAC = \[\boxed{60°}\]   ...[Remaining angle of a triangle]

∴ ∆ABC is 30° – 60° – 90° triangle.

∴ In ∆ABC by property of 30° – 60° – 90° triangle.

∴ AB = `1/2` AC   ...[Side opposite to 30°]

And \[\boxed{\text{BC}}\] = `sqrt(3)/2` AC   ...[Side opposite to 60°]

∴ \[\boxed{\text{AB}}\] = `1/2 xx 12` and BC = `sqrt(3)/2 xx 12`

∴ \[\boxed{\text{AB}}\] = 6 and BC = `6sqrt(3)`

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Chapter 2: Pythagoras Theorem - Q.2 (A)

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