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Question
Following table present educational level (middle stage) of females in Arunachal pradesh according to 1981 census:
| Age group | Number of females (to the nearest ten) |
| 10 - 14 | 300 |
| 15 - 19 | 980 |
| 20 - 24 | 800 |
| 25 - 29 | 380 |
| 30 - 34 | 290 |
Draw a histogram to represent the above data.
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Solution
Let us convert the given class intervals into continuous class intervals. Then the given frequency distribution takes the form:
| Age group | Number of females (to the nearest ten) |
| 9·5 - 14·5 | 300 |
| 14·5 - 19·5 | 980 |
| 19·5 - 24·5 | 800 |
| 24·5 - 29·5 | 380 |
| 29·5 - 34·5 | 290 |

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| 0 — 20 | 3 |
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Price of Sugar per kg (in Rs.) |
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Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.
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| Class | Frequency |
| 15-20 | 20 |
| 20-25 | 30 |
| 25-30 | 50 |
| 30-35 | 40 |
| 35-40 | 25 |
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Construct a histogram for the following data:
| Monthly school fee (in Rs): | 30−60 | 60−90 | 90−120 | 120−150 | 150−180 | 180−210 | 210−240 |
| Number of schools: | 5 | 12 | 14 | 18 | 10 | 9 | 4 |
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The graphical representation of ungrouped data is ________
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| Age | 41 − 45 | 46 − 50 | 51 − 55 | 56 − 60 | 61 − 65 | 66 − 70 | 71 − 75 |
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The given graph with a histogram represents the number of plants of different heights grown in a school campus. Study the graph carefully and answer the following questions:

- Make a frequency table with respect to the class boundaries and their corresponding frequencies.
- State the modal class.
- Identify and note down the mode of the distribution.
- Find the number of plants whose height range is between 80 cm to 90 cm.
