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Question
Draw a histogram and the frequency polygon in the same diagram to represent the following data
| Weight (in kg) | 50 − 55 | 56 − 61 | 62 − 67 | 68 − 73 | 74 − 79 | 80 − 85 | 86 − 91 |
| No. of persons | 15 | 8 | 12 | 17 | 9 | 10 | 6 |
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Solution
The given distribution is discontinuous.
Lower boundary = lower limit – `1/2` ...(gap between the adjacent class interval)
= `50 - 1/2` (1) = 49.5
Upper boundary = Upper limit + `1/2` ...(gap between the adjacent class interval)
= `55 + 1/2` (1) = 55.5
∴ The continuous frequency table is as below.
| Weight (in kg) | 49.5 − 55.5 | 55.5 − 61.5 | 61.5 − 67.5 | 67.5 − 73.5 | 73.5 − 79.5 | 79.5 − 85.5 | 85.5 − 91.5 |
| No. of persons | 15 | 8 | 12 | 17 | 9 | 10 | 6 |
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