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Question
Draw a histogram for the given frequency distribution
| Age | 41 − 45 | 46 − 50 | 51 − 55 | 56 − 60 | 61 − 65 | 66 − 70 | 71 − 75 |
| Frequency | 4 | 9 | 17 | 25 | 15 | 8 | 2 |
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Solution
The given distribution is discontinuous.
Lower boundary = lower limit – `1/2` (gap between the adjacent class interval)
= `41 - 1/2` (1) = 40.5
Upper boundary = Upper limit + `1/2` (gap between the adjacent class interval)
= `45 + 1/2` (1) = 45.5
Now continuous frequency table is as below
| Age | 40.5 − 45.5 | 45.5 − 50.5 | 50.5 − 55.5 | 55.5 − 60.5 | 60.5 − 65.5 | 65.5 − 70.5 | 70.5 − 75.5 |
| Frequency | 4 | 9 | 17 | 25 | 15 | 8 | 2 |
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Try yourself
- Next time when you watch your favourite TV programme, count the number of advertisements during each break. Use tally marks. Put a dot below the tally when you find children in any advertisement.
- Compare with your friends. Do you get different answers?
The height of a rectangle in a histogram shows the ______.
