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प्रश्न
Draw a histogram for the given frequency distribution
| Age | 41 − 45 | 46 − 50 | 51 − 55 | 56 − 60 | 61 − 65 | 66 − 70 | 71 − 75 |
| Frequency | 4 | 9 | 17 | 25 | 15 | 8 | 2 |
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उत्तर
The given distribution is discontinuous.
Lower boundary = lower limit – `1/2` (gap between the adjacent class interval)
= `41 - 1/2` (1) = 40.5
Upper boundary = Upper limit + `1/2` (gap between the adjacent class interval)
= `45 + 1/2` (1) = 45.5
Now continuous frequency table is as below
| Age | 40.5 − 45.5 | 45.5 − 50.5 | 50.5 − 55.5 | 55.5 − 60.5 | 60.5 − 65.5 | 65.5 − 70.5 | 70.5 − 75.5 |
| Frequency | 4 | 9 | 17 | 25 | 15 | 8 | 2 |
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संबंधित प्रश्न
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| 15-20 | 20 |
| 20-25 | 30 |
| 25-30 | 50 |
| 30-35 | 40 |
| 35-40 | 25 |
| 40-45 | 10 |
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| 20-25 | 2 |
| 25-30 | 5 |
| 30-35 | 8 |
| 35-40 | 12 |
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| 45-50 | 7 |
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| Cost of living Index | Number of months |
| 440 - 460 | 2 |
| 460 - 480 | 4 |
| 480 - 500 | 3 |
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| 520 - 540 | 3 |
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| 560 - 580 | 1 |
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| Total | 24 |
The graphical representation of ungrouped data is ________
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