Advertisements
Advertisements
Question
The time taken, in seconds, to solve a problem for each of 25 persons is as follows:
| 16 | 20 | 26 | 27 | 28 |
| 30 | 33 | 37 | 38 | 40 |
| 42 | 43 | 46 | 46 | 47 |
| 48 | 49 | 50 | 53 | 58 |
| 59 | 60 | 64 | 52 | 20 |
(i) Construct a frequency distribution for these data using a class interval of 10 seconds.
(ii) In a school the weekly pocket money of 50 students is as follow's:
| Weekly pocket money (₹) | No. of student |
| 40 - 50 | 2 |
| 59 - 60 | 8 |
| 60 - 70 | 12 |
| 70 - 80 | 14 |
| 80 - 90 | 8 |
| 90 - 100 | 6 |
Draw a histogram and a frequency polygon on the same graph. Find mode from the graph.
Advertisements
Solution
(i) Frequency table
| Time (in seconds) |
Tally marks | Frequency |
| 10 - 20 | I | 1 |
| 20 - 30 | IIIII | 5 |
| 30 - 40 | I I I I | 4 |
| 40 - 50 | IIII I I I I | 8 |
| 50 - 60 | IIIII | 5 |
| 60 - 70 | I I | 2 |
Histogram representing the time taken in seconds, to solve. A problem for each of 25 persons.
(ii) Frequency distribution table is
| Weekly pocket money (in ₹) | Class Marks | No. of Students |
| 40 - 50 | 45 | 2 |
| 50 - 60 | 55 | 8 |
| 60 - 70 | 65 | 12 |
| 70 - 80 | 75 | 14 |
| 80 - 90 | 85 | 8 |
| 90 - 100 | 95 | 6 |
Draw the histogram and frequency polygon on the graph.
Now, in the highest rectangle, draw two straight line AB and CD from the corners of the rectangle on either sides of the highest rectangle to opposite corners of the highest rectangle. They intersect P. Draw PR X-axis, then abscissa of the point prepresents ₹ 72·5.
Hence, the required mode is ₹72·5.
RELATED QUESTIONS
Represent the following data by Histogram:
|
Price of Sugar per kg (in Rs.) |
Number of Weeks |
| 18-20 | 4 |
| 20-22 | 8 |
| 22-24 | 22 |
| 24-26 | 12 |
| 26-28 | 8 |
| 28-30 | 6 |
The weekly wages (in Rs) of 30 workers in a factory are.
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840
Using tally marks make a frequency table with intervals as 800 − 810, 810 − 820 and so on.
Draw histogram and frequency polygon on the same graph paper for the following frequency distribution
| Class | Frequency |
| 15-20 | 20 |
| 20-25 | 30 |
| 25-30 | 50 |
| 30-35 | 40 |
| 35-40 | 25 |
| 40-45 | 10 |
The histogram below represents the scores obtained by 25 students in a mathematics mental test. Use the data to:
- Frame a frequency distribution table.
- To calculate mean.
- To determine the Modal class.

A Mathematics aptitude test of 50 students was recorded as follows:
| Marks | 50 - 60 | 60 - 70 | 70 - 80 | 80 - 90 | 90 – 100 |
| No. of Students | 4 | 8 | 14 | 19 | 5 |
Draw a histogram from the above data using a graph paper and locate the mode.
Construct histograms for following frequency distribution:
| Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| Frequency | 8 | 20 | 34 | 22 | 10 | 6 |
Draw histogram and hence the frequency polygon for the following frequency distribution:
| Rainfall (in cm) | No. of years |
| 20-25 | 2 |
| 25-30 | 5 |
| 30-35 | 8 |
| 35-40 | 12 |
| 40-45 | 10 |
| 45-50 | 7 |
The graphical representation of ungrouped data is ________
Histogram shows the number of people owning the different number of books. Answer the question based on it.

The total number of people surveyed is ______.
The following table shows the classification of percentage of marks of students and the number of students. Draw frequency polygon from the table without drawing histogram:
| Result (Percentage) | Number of Students |
| 20 - 40 | 25 |
| 40 - 60 | 65 |
| 60 - 80 | 80 |
| 80 - 100 | 15 |
