Advertisements
Advertisements
Question
Find the value of k in each of the following:
`(root(3)(8))^((-1)/(2)` = 2k
Sum
Advertisements
Solution
`(root(3)(8))^((-1)/(2)` = 2k
⇒ `8^(1/3 xx (-1)/(2))` = 2k
⇒ `(2^3)^(1/3 xx (-1)/2)` = 2k
⇒ `(2^3)^(1/3 xx (-1)/2)` = 2k
⇒ `2^((-1)/(2)` = 2k
⇒ k = `-(1)/(2)`.
shaalaa.com
Solving Exponential Equations
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Solve for x : 25x-1 = 4 23x + 1
Solve:
22x + 2x+2 − 4 × 23 = 0
If 5-P = 4-q = 20r, show that : `1/p + 1/q + 1/r = 0`
If m = `root(3)(15) and n = root(3)(14), "find the value of " m - n - 1/[ m^2 + mn + n^2 ]`
Evaluate the following:
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
Solve for x:
9x+4 = 32 x (27)x+1
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
