Advertisements
Advertisements
Question
Solve for x:
9x+4 = 32 x (27)x+1
Advertisements
Solution
9x+4 = 32 x (27)x+1
⇒ 9x+4 = 32 x (33)x+1
⇒ `3^(2(x+4) = 3^2 xx 3^(3x+3)`
⇒ `3^(2x+8) = 3^(2+3x+3)`
⇒2x + 8 = 2 + 3x + 3
⇒ 2x + 8 = 3x + 5
⇒ x = 3.
APPEARS IN
RELATED QUESTIONS
If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
If m = `root(3)(15) and n = root(3)(14), "find the value of " m - n - 1/[ m^2 + mn + n^2 ]`
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Evaluate the following:
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
Evaluate the following:
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Solve for x:
p3 x p-2 = px
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
