Evaluate the Following: 16 3 4 + 2 ( 1 2 ) − 1 × 3 0 - Mathematics

Evaluate the following:

`16^(3/4) + 2(1/2)^-1 xx 3^0`

Sum

`16^(3/4) + 2(1/2)^-1 xx 3^0`

= `2^(4 xx 3/4) + 2 xx 2 xx 1`
= 2³ + 4
= 2³ + 4
= 8 + 4
= 12.

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Solving Exponential Equations

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Chapter 9: Indices - Exercise 9.1

Chapter 9 Indices
Exercise 9.1 | Q 6.5

Find x, if : 4^2x = `1/32`

Find x, if : `sqrt( 2^( x + 3 )) = 16`

Solve : 4^{x - 2} - 2^{x + 1} = 0

Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`

Solve for x:

`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`

Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`

Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

Evaluate the following:

`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`

Find the value of (8p)^p if 9^{p + 2} - 9^p = 240.

Prove the following:

`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1