Advertisements
Advertisements
Question
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
Advertisements
Solution
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
= `(2^3 xx 3^5 xx (2^3 xx 3)^2)/((2^2 xx 3^2)^2 xx (2 xx 3^2)^3 xx (3^3))`
= `(2^3 xx 3^5 xx 2^6 xx 3^2)/(2^4 xx 3^2 xx 2^3 xx 3^6 xx 3^3)`
= `(2^9 xx 3^7)/(2^7 xx 3^11)`
= `(2^(9 - 7))/(3^(11 - 7))`
= `(2^2)/(3^4)`
= `(4)/(81)`.
APPEARS IN
RELATED QUESTIONS
Solve for x : 22x+1 = 8
Solve for x : (49)x + 4 = 72 x (343)x + 1
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`
Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
If 2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Evaluate the following:
`(1 - 15/64)^(-1/2)`
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
