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प्रश्न
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
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उत्तर
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
= `(2^3 xx 3^5 xx (2^3 xx 3)^2)/((2^2 xx 3^2)^2 xx (2 xx 3^2)^3 xx (3^3))`
= `(2^3 xx 3^5 xx 2^6 xx 3^2)/(2^4 xx 3^2 xx 2^3 xx 3^6 xx 3^3)`
= `(2^9 xx 3^7)/(2^7 xx 3^11)`
= `(2^(9 - 7))/(3^(11 - 7))`
= `(2^2)/(3^4)`
= `(4)/(81)`.
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संबंधित प्रश्न
Solve for x : 25x-1 = 4 23x + 1
Find x, if : 42x = `1/32`
Find x, if : `sqrt( 2^( x + 3 )) = 16`
Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`
Solve for x:
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
If 2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.
Solve for x:
22x+1= 8
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
