Advertisements
Advertisements
प्रश्न
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Advertisements
उत्तर
`4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
= `4/(6^3)^(-2/3) + 1/(4^4)^(-3/4) + 2/(3^5)^(-1/5)`
= `4/(6)^-2 + 1/(4)^-3 + 2/(3)^-1`
= 4 x 62 + 1 x 43 + 2 x 3
= 4 x 36 + 1 x 64 + 6
= 144 + 64 + 6
= 214
APPEARS IN
संबंधित प्रश्न
Solve for x : 22x+1 = 8
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Find the value of k in each of the following:
`(root(3)(8))^((-1)/(2)` = 2k
If ax = by = cz and abc = 1, show that
`(1)/x + (1)/y + (1)/z` = 0.
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
