Advertisements
Advertisements
प्रश्न
Solve:
22x + 2x+2 − 4 × 23 = 0
Advertisements
उत्तर
Given: 22x + 2x + 2 − 4 × 23 = 0
2(2x) + 2(x).2(2) − 4 × 8 = 0
Substituting 2x = a, we get:
a2 + 4a − 32 = 0
a2 + 8a − 4a − 32 = 0
a(a + 8) − 4(a + 8) = 0
(a − 4)(a + 8) = 0
a − 4 = 0 or a + 8 = 0
a = 4 or a = −8
a cannot be negative as 2x, for any value of x is greater than 0.
a = 4
2x = 4
2x = 22
x = 2
APPEARS IN
संबंधित प्रश्न
Find x, if : 42x = `1/32`
Solve : 4x - 2 - 2x + 1 = 0
Solve for x : (a3x + 5)2. (ax)4 = a8x + 12
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Solve for x:
2x + 3 + 2x + 1 = 320
Solve for x:
1 = px
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
