Advertisements
Advertisements
प्रश्न
Solve : 4x - 2 - 2x + 1 = 0
Advertisements
उत्तर
4x - 2 - 2x + 1 = 0
⇒ 4x - 2 = 2x + 1
⇒ (22)x - 2 = 2x + 1
⇒ 22x - 4 = 2x + 1
We know that if bases are equal, the powers are equal
⇒ 2x - 4 = x + 1
⇒ 2x - x = 4 + 1
⇒ x = 5.
APPEARS IN
संबंधित प्रश्न
Solve for x : 25x-1 = 4 23x + 1
Solve:
22x + 2x+2 − 4 × 23 = 0
Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
If 3x + 1 = 9x - 3 , find the value of 21 + x.
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Find the value of k in each of the following:
`(root(3)(8))^((-1)/(2)` = 2k
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
