22x+1= 8⇒ 22x+1= 23⇒ 2x + 1 = 3⇒ 2x = 2⇒ x = 1.

Solve for X: 22x+1= 8 - Mathematics

Solve for x:
2^2x+1= 8

बेरीज

2^2x+1= 8
⇒ 2^2x+1= 2³
⇒ 2x + 1 = 3
⇒ 2x = 2
⇒ x = 1.

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Solving Exponential Equations

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पाठ 9: Indices - Exercise 9.1

पाठ 9 Indices
Exercise 9.1 | Q 9.01

If 4^{x + 3} = 112 + 8 × 4^x, find the value of (18x)^3x.

If 5^{x + 1} = 25^{x - 2}, find the value of 3^{x - 3} × 2^{3 - x}.

Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`

If 3^{x + 1} = 9^{x - 3}, find the value of 2^{1 + x}.

Solve for x:
3 x 7^x = 7 x 3^x

Solve for x:
2^2x+3 - 9 x 2^x+ 1 = 0

Solve for x:

9 x 81^x = `(1)/(27^(x - 3)`

If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a³ + 6a = 3

If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)³ = 27xyz

If 2^x = 3^y = 12^z ; show that `(1)/z = (1)/y + (2)/x`.