22x+1= 8⇒ 22x+1= 23⇒ 2x + 1 = 3⇒ 2x = 2⇒ x = 1.

Solve for X: 22x+1= 8 - Mathematics

Solve for x:
2^2x+1= 8

योग

2^2x+1= 8
⇒ 2^2x+1= 2³
⇒ 2x + 1 = 3
⇒ 2x = 2
⇒ x = 1.

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Solving Exponential Equations

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अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 9.01

Solve for x : 2^2x+1 = 8

Solve for x : (49)^{x + 4} = 7²x (343)^{x + 1}

Solve : 8 x 2^2x + 4 x 2^{x + 1} = 1 + 2^x

Solve : 3^x-1× 5^2y-3 = 225.

Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`

Evaluate the following:

`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`

Evaluate the following:

`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`

Evaluate the following:

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

Solve for x:
2^{x + 3} + 2^{x + 1} = 320

Prove the following:

`(x^("p"("q"-"r")))/(x^("q"("p"-"r"))) ÷ (x^"q"/x^"p")^"r"` = 1