22x+1= 8⇒ 22x+1= 23⇒ 2x + 1 = 3⇒ 2x = 2⇒ x = 1.

Solve for X: 22x+1= 8

Solve for x:
2^2x+1= 8

योग

2^2x+1= 8
⇒ 2^2x+1= 2³
⇒ 2x + 1 = 3
⇒ 2x = 2
⇒ x = 1.

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Solving Exponential Equations

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अध्याय 6: Indices - Exercise 9.1

अध्याय 6 Indices
Exercise 9.1 | Q 9.01

Solve for x:

`3^(4x + 1) = (27)^(x + 1)`

If 4^{x + 3} = 112 + 8 × 4^x, find the value of (18x)^3x.

If a^x = b, b^y = c and c^z = a, prove that : xyz = 1.

Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`

If 3^{x + 1} = 9^{x - 3}, find the value of 2^{1 + x}.

Evaluate the following:

`(1 - 15/64)^(-1/2)`

Solve for x:
2^{x + 3} + 2^{x + 1} = 320

Solve for x:

`sqrt((8^0 + 2/3)` = (0.6)^2-3x

Find the value of k in each of the following:

`(1/3)^-4 ÷ 9^((-1)/(3)` = 3^k

If `root(x)("a") = root(y)("b") = root(z)("c")` and abc = 1, prove that x + y + z = 0