1 = px⇒ p0 = px ......(Using a0 = 1)⇒ x = 0.

Solve for X: 1 = Px - Mathematics

Solve for x:
1 = p^x

बेरीज

1 = p^x
⇒ p⁰ = p^x ......(Using a⁰= 1)
⇒ x = 0.

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Solving Exponential Equations

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पाठ 9: Indices - Exercise 9.1

पाठ 9 Indices
Exercise 9.1 | Q 9.06

Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`

Solve for x:

`2^(3x + 3) = 2^(3x + 1) + 48`

If a^x = b^y = c^z and b² = ac, prove that: y = `[2xz]/[x + z]`

If 2^x = 4^y = 8^z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.

If m = `root(3)(15) and n = root(3)(14), "find the value of " m - n - 1/[ m^2 + mn + n^2 ]`

Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`

Evaluate the following:

`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`

Evaluate the following:

`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`

Solve for x:
2^2x+1= 8

If a^x = b^y = c^z and b² = ac, prove that y = `(2xz)/(z + x)`