1 = px⇒ p0 = px ......(Using a0 = 1)⇒ x = 0.

Solve for X: 1 = Px | Shaalaa.com

Solve for x:
1 = p^x

Sum

1 = p^x
⇒ p⁰ = p^x ......(Using a⁰= 1)
⇒ x = 0.

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Solving Exponential Equations

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Chapter 9: Indices - Exercise 9.1

Chapter 9 Indices
Exercise 9.1 | Q 9.06

Find x, if : `sqrt( 2^( x + 3 )) = 16`

Solve : 8 x 2^2x + 4 x 2^{x + 1} = 1 + 2^x

Solve for x:

`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`

Solve for x:

`2^(3x + 3) = 2^(3x + 1) + 48`

Solve x and y if : ( √32 )^x ÷ 2^{y + 1} = 1 and 8^y - 16^{4 - x/2} = 0

Solve for x:
`9 xx 3^x = (27)^(2x - 5)`

Solve for x:
2^{x + 3} + 2^{x + 1} = 320

If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)³ = 27xyz

Find the value of 'a' and 'b' if:

`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0

Prove the following:

`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1

Solve for X: 1 = Px