1 = px⇒ p0 = px ......(Using a0 = 1)⇒ x = 0.

Solve for X: 1 = Px - Mathematics

Solve for x:
1 = p^x

योग

1 = p^x
⇒ p⁰ = p^x ......(Using a⁰= 1)
⇒ x = 0.

shaalaa.com

Solving Exponential Equations

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 9.06

Solve for x : 2^2x+1 = 8

Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`

Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`

If 3^{x + 1} = 9^{x - 3}, find the value of 2^{1 + x}.

If 2^x = 4^y = 8^z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.

Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`

Evaluate the following:

`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`

Solve for x:

`"p"^-5 = (1)/"p"^(x + 1)`

If a^x = b^y = c^z and b² = ac, prove that y = `(2xz)/(z + x)`

If 2250 = 2^a. 3^b. 5^c, find a, b and c. Hence, calculate the value of 3^a x 2^-b x 5^-c.