1 = px⇒ p0 = px ......(Using a0 = 1)⇒ x = 0.

Solve for X: 1 = Px - Mathematics

Solve for x:
1 = p^x

योग

1 = p^x
⇒ p⁰ = p^x ......(Using a⁰= 1)
⇒ x = 0.

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Solving Exponential Equations

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अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 9.06

Solve for x : 2^2x+1 = 8

Solve : 8 x 2^2x + 4 x 2^{x + 1} = 1 + 2^x

If 5^-P = 4^-q = 20^r, show that : `1/p + 1/q + 1/r = 0`

If a^x = b^y = c^z and b² = ac, prove that: y = `[2xz]/[x + z]`

If a^x = b, b^y = c and c^z = a, prove that : xyz = 1.

Solve for x:
2^2x+1= 8

Find the value of k in each of the following:

`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3^k

Find the value of k in each of the following:

`(1/3)^-4 ÷ 9^((-1)/(3)` = 3^k

If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)³ = 27xyz

If 2^x = 3^y = 12^z ; show that `(1)/z = (1)/y + (2)/x`.