Advertisements
Advertisements
प्रश्न
Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
Advertisements
उत्तर
`(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
⇒ `(3^(1/2))^( x - 3 ) = (3^(1/4))^( x + 1 )`
⇒ `3^[( x - 3)/2] = 3^[( x + 1 )/4]`
⇒ `[ x - 3 ]/2 = [ x + 1 ]/4`
⇒ 4( x - 3 ) = 2( x + 1 )
⇒ 4x - 12 = 2x + 2
⇒ 4x - 2x = 12 + 2
⇒ 2x = 14
⇒ x = `14/2`
⇒ x = 7
APPEARS IN
संबंधित प्रश्न
Solve for x : 25x-1 = 4 23x + 1
Simplify : `[ 3 xx 9^( n + 1 ) - 9 xx 3^(2n)]/[3 xx 3^(2n + 3) - 9^(n + 1 )]`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
Solve for x:
2x + 3 + 2x + 1 = 320
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
Prove the following:
`(x^("p"("q"-"r")))/(x^("q"("p"-"r"))) ÷ (x^"q"/x^"p")^"r"` = 1
