Advertisements
Advertisements
प्रश्न
Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
Advertisements
उत्तर
`(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
⇒ `(3^(1/2))^( x - 3 ) = (3^(1/4))^( x + 1 )`
⇒ `3^[( x - 3)/2] = 3^[( x + 1 )/4]`
⇒ `[ x - 3 ]/2 = [ x + 1 ]/4`
⇒ 4( x - 3 ) = 2( x + 1 )
⇒ 4x - 12 = 2x + 2
⇒ 4x - 2x = 12 + 2
⇒ 2x = 14
⇒ x = `14/2`
⇒ x = 7
APPEARS IN
संबंधित प्रश्न
Solve for x : 3(2x + 1) - 2x + 2 + 5 = 0
If 5-P = 4-q = 20r, show that : `1/p + 1/q + 1/r = 0`
If ax = b, by = c and cz = a, prove that : xyz = 1.
Evaluate the following:
`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
If ax = by = cz and b2 = ac, prove that y = `(2xz)/(z + x)`
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
Find the value of 'a' and 'b' if:
`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
