Advertisements
Advertisements
प्रश्न
Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
Advertisements
उत्तर
`(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
⇒ `(3^(1/2))^( x - 3 ) = (3^(1/4))^( x + 1 )`
⇒ `3^[( x - 3)/2] = 3^[( x + 1 )/4]`
⇒ `[ x - 3 ]/2 = [ x + 1 ]/4`
⇒ 4( x - 3 ) = 2( x + 1 )
⇒ 4x - 12 = 2x + 2
⇒ 4x - 2x = 12 + 2
⇒ 2x = 14
⇒ x = `14/2`
⇒ x = 7
APPEARS IN
संबंधित प्रश्न
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Solve : 4x - 2 - 2x + 1 = 0
Solve:
22x + 2x+2 − 4 × 23 = 0
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
Solve : 3x-1× 52y-3 = 225.
If 2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk
If 2250 = 2a. 3b. 5c, find a, b and c. Hence, calculate the value of 3a x 2-b x 5-c.
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
