Advertisements
Advertisements
प्रश्न
Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
Advertisements
उत्तर
`(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
⇒ `(3^(1/2))^( x - 3 ) = (3^(1/4))^( x + 1 )`
⇒ `3^[( x - 3)/2] = 3^[( x + 1 )/4]`
⇒ `[ x - 3 ]/2 = [ x + 1 ]/4`
⇒ 4( x - 3 ) = 2( x + 1 )
⇒ 4x - 12 = 2x + 2
⇒ 4x - 2x = 12 + 2
⇒ 2x = 14
⇒ x = `14/2`
⇒ x = 7
APPEARS IN
संबंधित प्रश्न
Solve:
22x + 2x+2 − 4 × 23 = 0
If ax = b, by = c and cz = a, prove that : xyz = 1.
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
If m = `root(3)(15) and n = root(3)(14), "find the value of " m - n - 1/[ m^2 + mn + n^2 ]`
Evaluate the following:
`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Prove the following:
(xa)b-c x (xb)c-a x (xc)a-b = 1
