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प्रश्न
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
योग
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उत्तर
9x 3x = (27)2x- 5
⇒ 32 x 3x = (33)2x- 5
⇒ 32 x 3x = `3^(3x^((2x - 5))`
⇒ 32+x = 36x-15
⇒ 1 = `(3^(6x - 15))/(3^(2 + x))`
⇒ 1 = `3^(6x - 15 - 2 - x)`
⇒ 30 = 35x-17
⇒ 5x 17 = 0
⇒ x = `(17)/(5)`.
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Solving Exponential Equations
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