Advertisements
Advertisements
प्रश्न
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
Advertisements
उत्तर
5x + 1 = 25x - 2
⇒ 5x + 1 = (52)x - 2
⇒ 5x + 1 = 52x - 4
If bases are equal, powers are also equal.
⇒ x + 1 = 2x - 4
⇒ 2x - x = 4 + 1
⇒ x = 5
∴ 3x - 3 x 23 - x
= 35 - 3 x 23 - 5
= 32 x 2-2
= 9 x `1/4 = 9/4`
APPEARS IN
संबंधित प्रश्न
Solve for x : 25x-1 = 4 23x + 1
Solve for x:
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
Solve for x : 3(2x + 1) - 2x + 2 + 5 = 0
If ax = by = cz and b2 = ac, prove that: y = `[2xz]/[x + z]`
Evaluate the following:
`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk
Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
Find the value of (8p)p if 9p + 2 - 9p = 240.
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
