Advertisements
Advertisements
प्रश्न
Solve for x:
2x + 3 + 2x + 1 = 320
Advertisements
उत्तर
2x + 3 + 2x + 1 = 320
⇒ 2x + 3 + 2x + 1 = 26 x 5
⇒ 2x . 23 + 2x . 21 = 26 x 5
⇒ 2x (23 + 21) = 26 x 5
⇒ 2x (8 + 2) = 26 x 5
⇒ 2x (10) = 26 x 5
⇒ `2^x (10/5)` = 26
⇒ 2x . 2 = 26
⇒ `(2^x . 2)/(2^6)` = 1
⇒ `2^(x +1 - 6)` = 1 x 20
⇒ `2^(x - 5)` = 1 x 20
⇒ x - 5 = 0
⇒ x = 5.
APPEARS IN
संबंधित प्रश्न
Solve for x : 25x-1 = 4 23x + 1
Solve : 8 x 22x + 4 x 2x + 1 = 1 + 2x
Simplify : `[ 3 xx 9^( n + 1 ) - 9 xx 3^(2n)]/[3 xx 3^(2n + 3) - 9^(n + 1 )]`
If 3x + 1 = 9x - 3 , find the value of 21 + x.
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
Prove the following:
`(x^("p"("q"-"r")))/(x^("q"("p"-"r"))) ÷ (x^"q"/x^"p")^"r"` = 1
