Solve for X : 3(2x + 1) - 2x + 2 + 5 = 0

Solve for x : 3(2^x + 1) - 2^{x + 2} + 5 = 0

योग

3(2^x + 1) - 2^{x + 2} + 5 = 0
⇒ 3 x 2^x + 3 - 2^x x 2² + 5 = 0
⇒ 2^x ( 3 - 4 ) + 8 = 0
⇒ - 2^x= - 8
⇒ 2^x= 2³⇒ x = 3

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Solving Exponential Equations

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अध्याय 7: Indices (Exponents) - Exercise 7 (B) [पृष्ठ १०१]

अध्याय 7 Indices (Exponents)
Exercise 7 (B) | Q 14.5 | पृष्ठ १०१

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