Advertisements
Advertisements
Question
Solve:
22x + 2x+2 − 4 × 23 = 0
Advertisements
Solution
Given: 22x + 2x + 2 − 4 × 23 = 0
2(2x) + 2(x).2(2) − 4 × 8 = 0
Substituting 2x = a, we get:
a2 + 4a − 32 = 0
a2 + 8a − 4a − 32 = 0
a(a + 8) − 4(a + 8) = 0
(a − 4)(a + 8) = 0
a − 4 = 0 or a + 8 = 0
a = 4 or a = −8
a cannot be negative as 2x, for any value of x is greater than 0.
a = 4
2x = 4
2x = 22
x = 2
APPEARS IN
RELATED QUESTIONS
Solve for x : 9x+2 = 720 + 9x
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
Solve : 3x-1× 52y-3 = 225.
If 2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.
Evaluate the following:
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
