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Solve: 22x + 2x+2 − 4 × 23 = 0 - Mathematics

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Question

Solve: 

22x + 2x+2 − 4 × 23 = 0

Sum
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Solution

Given: 22x + 2x + 2 − 4 × 23 = 0

2(2x) + 2(x).2(2) − 4 × 8 = 0

Substituting 2x = a, we get:

a2 + 4a − 32 = 0

a2 + 8a − 4a − 32 = 0

a(a + 8) − 4(a + 8) = 0

(a − 4)(a + 8) = 0

a − 4 = 0 or a + 8 = 0

a = 4 or a = −8

a cannot be negative as 2x, for any value of x is greater than 0.

a = 4

2x = 4

2x = 22

x = 2

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Solving Exponential Equations
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Chapter 7: Indices (Exponents) - Exercise 7 (B) [Page 100]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (B) | Q 4.2 | Page 100
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