Evaluate the Following: 16 3 4 + 2 ( 1 2 ) − 1 × 3 0

Evaluate the following:

`16^(3/4) + 2(1/2)^-1 xx 3^0`

बेरीज

`16^(3/4) + 2(1/2)^-1 xx 3^0`

= `2^(4 xx 3/4) + 2 xx 2 xx 1`
= 2³ + 4
= 2³ + 4
= 8 + 4
= 12.

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Solving Exponential Equations

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पाठ 9: Indices - Exercise 9.1

पाठ 9 Indices
Exercise 9.1 | Q 6.5

Solve for x : 2^2x+1 = 8

Solve for x : 2^5x-1 = 4 2^{3x + 1}

Solve : 8 x 2^2x + 4 x 2^{x + 1} = 1 + 2^x

Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`

Solve for x:

`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`

If 5^{x + 1} = 25^{x - 2}, find the value of 3^{x - 3} × 2^{3 - x}.

Evaluate the following:

`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`

Evaluate the following:

`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`

Solve for x:
`9 xx 3^x = (27)^(2x - 5)`

Solve for x:
p³ x p^-2 = p^x