Advertisements
Advertisements
Question
Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
Advertisements
Solution
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
⇒ `{(3^2)^(1/2)}^-7 {(3)^(1/2)}^-5` = 3k
⇒ `3^-7 xx 3^((-5)/2)` = 3k
⇒ `3^(-7 -5/2)` = 3k
⇒ `3^((-14 - 5)/(2)` = 3k
⇒ `3^((-19)/(2)` = 3k
⇒ k = `(-19)/(2)`.
APPEARS IN
RELATED QUESTIONS
Solve for x : 9x+2 = 720 + 9x
Solve for x : (a3x + 5)2. (ax)4 = a8x + 12
If ax = by = cz and b2 = ac, prove that: y = `[2xz]/[x + z]`
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
Solve x and y if : ( √32 )x ÷ 2y + 1 = 1 and 8y - 164 - x/2 = 0
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
