Advertisements
Advertisements
Question
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
Advertisements
Solution
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
⇒ `(3^-1)^-4 ÷ (3^2)^((-1)/(2)` = 3k
⇒ `3^4 ÷ 3^((-2)/(3)` = 3k
⇒ `3^(4 + 2/3)` = 3k
⇒ `3^(14/3)` = 3k
⇒ k = `(14)/(3)`.
APPEARS IN
RELATED QUESTIONS
Solve for x : 25x-1 = 4 23x + 1
Solve for x:
`3^(4x + 1) = (27)^(x + 1)`
If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.
If 5-P = 4-q = 20r, show that : `1/p + 1/q + 1/r = 0`
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
Solve for x:
2x + 3 + 2x + 1 = 320
If `root(x)("a") = root(y)("b") = root(z)("c")` and abc = 1, prove that x + y + z = 0
If ax = by = cz and abc = 1, show that
`(1)/x + (1)/y + (1)/z` = 0.
Prove the following:
(xa)b-c x (xb)c-a x (xc)a-b = 1
