Advertisements
Advertisements
Question
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
Advertisements
Solution
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
⇒ `(3^-1)^-4 ÷ (3^2)^((-1)/(2)` = 3k
⇒ `3^4 ÷ 3^((-2)/(3)` = 3k
⇒ `3^(4 + 2/3)` = 3k
⇒ `3^(14/3)` = 3k
⇒ k = `(14)/(3)`.
APPEARS IN
RELATED QUESTIONS
Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`
Find the values of m and n if :
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`
If m = `root(3)(15) and n = root(3)(14), "find the value of " m - n - 1/[ m^2 + mn + n^2 ]`
Evaluate the following:
`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`
Evaluate the following:
`(1 - 15/64)^(-1/2)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
Prove the following:
`("a"^"m"/"a"^"n")^("m"+"n"+1) ·("a"^"n"/"a"^1)^("n" + 1-"m").("a"^1/"a"^"m")^(1+"m"-"n")`
