Solve for X : 9x+2 = 720 + 9x

Solve for x : 9^x+2= 720 + 9^x

Sum

9^x+2= 720 + 9^x⇒ 9^x+2 - 9^x = 720
⇒ 9^x (9² - 1) = 720
⇒ 9^x (81 - 1) = 720
⇒ 9^x (80) = 720
⇒ 9^x = 9
⇒ 9^x = 9¹⇒ x = 1

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Solving Exponential Equations

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Chapter 7: Indices (Exponents) - Exercise 7 (B) [Page 101]

Chapter 7 Indices (Exponents)
Exercise 7 (B) | Q 14.6 | Page 101

Solve for x : 2^5x-1 = 4 2^{3x + 1}

Solve : 4^{x - 2} - 2^{x + 1} = 0

Evaluate the following:

`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`

Evaluate the following:

`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`

Evaluate the following:

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

Evaluate the following:

`16^(3/4) + 2(1/2)^-1 xx 3^0`

Solve for x:
1 = p^x

Solve for x:

9 x 81^x = `(1)/(27^(x - 3)`

Solve for x:
9^x+4= 3² x (27)^x+1

Prove the following:
(x^a)^b-c x (x^b)^c-a x (x^c)^a-b= 1