Advertisements
Advertisements
प्रश्न
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
योग
Advertisements
उत्तर
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
⇒ `(3^-1)^-4 ÷ (3^2)^((-1)/(2)` = 3k
⇒ `3^4 ÷ 3^((-2)/(3)` = 3k
⇒ `3^(4 + 2/3)` = 3k
⇒ `3^(14/3)` = 3k
⇒ k = `(14)/(3)`.
shaalaa.com
Solving Exponential Equations
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Solve for x : (a3x + 5)2. (ax)4 = a8x + 12
If ax = b, by = c and cz = a, prove that : xyz = 1.
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
Solve for x:
22x+1= 8
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
